X^2-248x-480=0

Solution for X^2-248x-480=0 equation:

X^2-248X-480=0

a = 1; b = -248; c = -480;
Δ = b2-4ac
Δ = -2482-4·1·(-480)
Δ = 63424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{63424}=\sqrt{64*991}=\sqrt{64}*\sqrt{991}=8\sqrt{991}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-248)-8\sqrt{991}}{2*1}=\frac{248-8\sqrt{991}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-248)+8\sqrt{991}}{2*1}=\frac{248+8\sqrt{991}}{2}
$